I remember standing here
Right on this very same site
I was dying but for you
It was just another night
You once rocked me in your world
You bought me my first shoes
I was just another lonely child
Oh and you were much amused
So you took me and you dressed me well
All for your friends to see
Drained my body calmly till
There was no more left in me
Then you walked out and you cut me cold
Out on the road somewhere
Why it happened well I don't know
And I still have no idea
But everybody needs a friend sometimes
You need a little help
And who knows maybe one day you'll seek mine
Only time will tell
You once held me in your arms
You made me feel so right
I was flying but for you
It was just another night
But everybody needs a little help
Whether or not you think you really do
Everybody needs a little help
Now the time has come for you
I ain't looking to fight no wars
No more talking trash
I'm not seeking any more pain
Cause i've had enough of that
But don't you worry it's alright
If you should come around
Any night or any day
I won't ever let you down
Nežinau nežinau, daug kas negali pasitraukti visiškai iš Chrome, pavyzdžiui, jeigu reikia dėl darbo. Ir šiaip Chromium ne be reikalo lyderiauja, nes pasižymi stabilumu ir geru funkcionalumu. Bet Firefox dabar gera alternatyva jei rūpi privatumas.
Pastaruosius kelis metus žmonės migruoja į Firefox (nes užkniso Chromium naršyklių įvairūs bullshit'ai) arba į Brave (dėl privatumo opcijų). Chrome ilgainiui pataps old news, manau.
Aš iš Chrome emigravau prieš 4-5 metus, and never looked back. Dabar naudoju išimtinai MS Edge, tiesiog geresnė naršyklė (kažkas, ką Microsoft'as sugebėjo padaryti gerai, kas yra keista).
Jei Chrome, tai užuojauta. Jei kitka, tai yra lengvų sprendimų. MS Edge + uBlock origin veikia puikiai man. Girdėjau, kad Firefox + uBlock origin irgi čiki piki. Nežinau, kokie sprendimai kitoms naršyklėms.
Man irgi buvo problema su "1. ", bet pasirodo edzkaa tiesiog plug-in'o neįdėjo, kadangi visi netelpa. Tai aš tiesiog sugalvojau panaikinti taškus, ir rašyti tiesiog skaičius.